\(\int \frac {x}{(a+b \sec ^{-1}(c x))^2} \, dx\) [39]

Optimal result

Integrand size = 12, antiderivative size = 12 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\text {Int}\left (\frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2},x\right ) \]

[Out]

Unintegrable(x/(a+b*arcsec(c*x))^2,x)

Rubi [N/A]

Not integrable

Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx \]

[In]

Int[x/(a + b*ArcSec[c*x])^2,x]

[Out]

Defer[Int][x/(a + b*ArcSec[c*x])^2, x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 11.91 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx \]

[In]

Integrate[x/(a + b*ArcSec[c*x])^2,x]

[Out]

Integrate[x/(a + b*ArcSec[c*x])^2, x]

Maple [N/A] (verified)

Not integrable

Time = 0.56 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00

\[\int \frac {x}{\left (a +b \,\operatorname {arcsec}\left (c x \right )\right )^{2}}d x\]

[In]

int(x/(a+b*arcsec(c*x))^2,x)

[Out]

int(x/(a+b*arcsec(c*x))^2,x)

Fricas [N/A]

Not integrable

Time = 0.27 (sec) , antiderivative size = 28, normalized size of antiderivative = 2.33 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int { \frac {x}{{\left (b \operatorname {arcsec}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x/(a+b*arcsec(c*x))^2,x, algorithm="fricas")

[Out]

integral(x/(b^2*arcsec(c*x)^2 + 2*a*b*arcsec(c*x) + a^2), x)

Sympy [N/A]

Not integrable

Time = 0.93 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int \frac {x}{\left (a + b \operatorname {asec}{\left (c x \right )}\right )^{2}}\, dx \]

[In]

integrate(x/(a+b*asec(c*x))**2,x)

[Out]

Integral(x/(a + b*asec(c*x))**2, x)

Maxima [N/A]

Not integrable

Time = 0.95 (sec) , antiderivative size = 583, normalized size of antiderivative = 48.58 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int { \frac {x}{{\left (b \operatorname {arcsec}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x/(a+b*arcsec(c*x))^2,x, algorithm="maxima")

[Out]

-(4*(b*x^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)) + a*x^2)*sqrt(c*x + 1)*sqrt(c*x - 1) - (4*b^3*arctan(sqrt(c*x +
1)*sqrt(c*x - 1))^2 + b^3*log(c^2*x^2)^2 + 4*b^3*log(c)^2 + 8*b^3*log(c)*log(x) + 4*b^3*log(x)^2 + 8*a*b^2*ar
ctan(sqrt(c*x + 1)*sqrt(c*x - 1)) + 4*a^2*b - 4*(b^3*log(c) + b^3*log(x))*log(c^2*x^2))*integrate(-4*(3*a*c^2*
x^3 - 2*a*x + (3*b*c^2*x^3 - 2*b*x)*arctan(sqrt(c*x + 1)*sqrt(c*x - 1)))*sqrt(c*x + 1)*sqrt(c*x - 1)/(4*b^3*lo
g(c)^2 + 4*a^2*b - 4*(b^3*c^2*log(c)^2 + a^2*b*c^2)*x^2 - 4*(b^3*c^2*x^2 - b^3)*arctan(sqrt(c*x + 1)*sqrt(c*x
- 1))^2 - (b^3*c^2*x^2 - b^3)*log(c^2*x^2)^2 - 4*(b^3*c^2*x^2 - b^3)*log(x)^2 - 8*(a*b^2*c^2*x^2 - a*b^2)*arct
an(sqrt(c*x + 1)*sqrt(c*x - 1)) + 4*(b^3*c^2*x^2*log(c) - b^3*log(c) + (b^3*c^2*x^2 - b^3)*log(x))*log(c^2*x^2
) - 8*(b^3*c^2*x^2*log(c) - b^3*log(c))*log(x)), x))/(4*b^3*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))^2 + b^3*log(c^
2*x^2)^2 + 4*b^3*log(c)^2 + 8*b^3*log(c)*log(x) + 4*b^3*log(x)^2 + 8*a*b^2*arctan(sqrt(c*x + 1)*sqrt(c*x - 1))
+ 4*a^2*b - 4*(b^3*log(c) + b^3*log(x))*log(c^2*x^2))

Giac [N/A]

Not integrable

Time = 105.84 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.17 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int { \frac {x}{{\left (b \operatorname {arcsec}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x/(a+b*arcsec(c*x))^2,x, algorithm="giac")

[Out]

integrate(x/(b*arcsec(c*x) + a)^2, x)

Mupad [N/A]

Not integrable

Time = 0.78 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.50 \[ \int \frac {x}{\left (a+b \sec ^{-1}(c x)\right )^2} \, dx=\int \frac {x}{{\left (a+b\,\mathrm {acos}\left (\frac {1}{c\,x}\right )\right )}^2} \,d x \]

[In]

int(x/(a + b*acos(1/(c*x)))^2,x)

[Out]

int(x/(a + b*acos(1/(c*x)))^2, x)